Derive 1+2+3+4+5+6+7+8+.......=-1/12

Step By Step Easy derivation of Ramanujan equation of infinity

Let , S = 1+2+3+4+5+6+7+8+.......

If X = 1-1+1-1+1-1+1............
1-X = 1-1+1-1+1-1.......
1-X = X
2X = 1
X = 1/2

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If Y = 1-2+3-4+5-6..........
Y =  +1-2+3-5+6..........
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2Y = 1-1+1-1+1-1......
2Y =X
=> Y = X/2 = 1/4
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S=1+2+3+4+5+6.....

S-Y = 1+2+3+4+5+6+....
     -1+2-3+4-5+6+....
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S-Y = 0+4+0+8+0+12+.....
S-Y = 4(1+2+3+4..........)

S-Y = 4S

3S = -Y => S = -Y/3 = -1/12

So , 1+2+3+4+5.................= -1/12